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12 July 2018, 16:07
With Justin Bieber and Hailey Baldwin now engaged, will it make their matching ink with Selena a bit awkward?
When Justin Bieber and Hailey Baldwin revealed that they were engaged, everyone was pretty surprised. Our surprise didn't last long though because we soon remembered that the couple actually share ink with Justin's ex Selena Gomez!
Whilst Justin has got plenty of tattoos with hidden meanings, back in 2015, the trio all got inked with the same thing and now that the big engagement news has dropped, it's got everyone talking.
The tattoo in question is an inking of the letter 'G' and there was reportedly a very special reason why Justin, Selena and Hailey all got it done at the same time.
Hailey Baldwin Tattoo - Pic: Instagram
Selena Gomez Tattoo - Pic: Getty
The trio all got the tattoo as a tribute to a girl named Georgia, who is the daughter of Seattle Megachurch Pastor Chad Veach and his wife Julia. Georgia was born with a rare brain disorder called Lissencephaly and Justin, Hailey and plenty of other celebs got the 'G' in her honour, supposedly including Selena Gomez.
Selena later claimed that her ink was actually a tribute to her half-sister Gracie, who had been born after Selena's mum had suffered a miscarriage with her other sister Scarlett just two years before, but that didn't stop rumours circulating at the time.
I think "G" tattoos are in trend ... First Selena then Hailey and now Justin— hopeless love (@newlife_G) July 9, 2015
Hailey getting a ''g'' tattoo like selena? ok. but on the same place? literally the same tattoo? this cannot be a coincidence— ً (@chersxlloyd) June 26, 2015
Hailey and Selena got the same tattoo what does the "g" mean?— laura (@lovinggmz) June 18, 2015
Justin, Hailey, and Selena all have 'g' tattoos— Z (@Justinbiebbruh) July 9, 2015
There is no sign that either Justin, Selena or Hailey will look to cover up their 'G' tattoo or remove it now that Justin's future wife will have the same ink as his ex, but if they are completely seperate then why would they?